add a custom function on angular $resource

angularjs, angularjs-resource, angularjs-scope, javascript

Solution

You can add it as a property using transformResponse, but might I suggest just adding a method to every object that returns the combined first and last name:

app.factory('User', function ($resource) {
    var User = $resource(
        '/api/user/:listCtrl:id/:docCtrl/', {
            id: '@id',
            listCtrl: '@listCtrl',
            docCtrl: '@docCtrl'
        }, {
            update: {
                method: 'PUT'
            },
            current: {
                method: 'GET',
                params: {
                    listCtrl: 'current'
                }
            },
            nearby: {
                method: 'GET',
                params: {
                    docCtrl: 'nearby'
                },
                isArray: true
            }
        }
    );
    // add any methods here using prototype
    User.prototype.get_full_name = function() {
        return this.first_name + ' ' + this.last_name;
    };
    return User;
});

Then use:

<p>{{ user.get_full_name() }}</p>

Any functions added using prototype will be added onto every object returned by your Service. It is a great way to add helper methods if you need to do complicated getting or setting of service properties.

Problem

I have an angular resource that goes something like this ``` app.factory('User', function ($resource) { return $resource( '/api/user/:listCtrl:id/:docCtrl/', { id: '@id', listCtrl: '@listCtrl', docCtrl: '@docCtrl' }, { update: { method: 'PUT' }, current: { method: 'GET', params: { listCtrl: 'current' } }, nearby: { method: 'GET', params: { docCtrl: 'nearby' }, isArray: true } } ); }); ``` now i want to have full name in the view, can i add a method so that when i do this ``` $scope.user = User().current(); ``` instead of doing the following in html ``` <p>{{ user.first_name }} {{ user.last_name }}</p> ``` i do this ``` <p>{{ user.get_full_name }}</p> ``` is there a way to add this property to the `$resource`?

Original source

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