Comparing character arrays with an == operator in C
arrays, c, string-comparison
Solution
The == is comparing the memory address. It's likely that your compiler is making s1 and s2 point to the same static data to save space.
ie. The "Andreas" in the first two lines of code is stored in your executable data. The C standard says these strings are constant and so has optomized the two pointers to point to the same storage.
The char[] lines create a variable by copying the data into the variable and so are stored at different address on the stack during execution.
Problem
I know that the correct way to compare "strings" in C is by using `strcmp`, but now I tried comparing some character arrays with the `==` operator, and got some strange results. Take a look at the following code: ``` int main() { char *s1 = "Andreas"; char *s2 = "Andreas"; char s3[] = "Andreas"; char s4[] = "Andreas"; char *s5 = "Hello"; printf("%d\n", s1 == s2); //1 printf("%d\n", s3 == s4); //0 printf("%d\n", s1 == s5); //0 } ``` The first `printf` correctly prints a `1`, which signals that they are not equal. But can someone explain to me why, when comparing the character arrays, the `==` is returning a `0` ? Can someone please explain to me why the first `printf` is returning a `1` (ie, they are equal) and the character arrays are returning a `0` ?