Error unzipping a file in cmd (using 7z in Windows)
7zip, cmd
Solution
The option is `-o`, not `o-`. Run the command like this:
7z e recording_20130731180507.zip -o"C:\users\User1\documents\folder1\test"
Problem
I am attempting to use 7 Zip through the command line. As you can see below, using the command `7z l` lists the 3 files in the target zip file. ``` C:\Users\User1\Downloads>7z l recording_20130731180507.zip -- Path = recording_20130731180507.zip Type = zip Physical Size = 311686 Date Time Attr Size Compressed Name ------------------- ----- ------------ ------------ ------------------------ 2013-07-31 18:05:06 ..... 655 655 SD_DISK\20130731\18\2013073 1_180505_A4BC_00408CC2B40B\recording.xml 2013-07-31 18:05:06 ..... 309752 309752 SD_DISK\20130731\18\2013073 1_180505_A4BC_00408CC2B40B\20130731_18\20130731_180505_59EB_00408CC2B40B.mkv 2013-07-31 18:05:06 ..... 279 279 SD_DISK\20130731\18\2013073 1_180505_A4BC_00408CC2B40B\20130731_18\20130731_180505_59EB_00408CC2B40B.xml ------------------- ----- ------------ ------------ ------------------------ 310686 310686 3 files, 0 folders ``` However, when I attempt to actually unzip the file, I get a "no files to process error". I've never tried unzipping from cmd before. Do I have to try to dig into the zip file to extract those 3 files? ``` C:\Users\User1\Downloads>7z e recording_20130731180507.zip o-C:\users\User1\do cuments\folder1\test No files to process Files: 0 Size: 0 Compressed: 311686 ```