bitwise AND in java with operator "&"

bitwise-and, bitwise-operators, java

Solution

No, it doesn't.

if(bts[i] == 0x01)

means if bts[i] is equal to 1.

if((bts[i] & 0x01) == 0x01)

means if the least significant bit of bts[i] is equal to 1.

Example.

bts[i] = 9 //1001 in binary

if(bts[i] == 0x01) //false

if((bts[i] & 0x01) == 0x01) //true

Problem

I just read this code following: ``` byte[] bts = {8, 0, 0, 0}; if ((bts[i] & 0x01) == 0x01) ``` Does this do the same thing as ``` if (bts[i] == 0x01) ``` If not,what's the difference between them? And what is the first way trying to do here?

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