How to find the duration of difference between two dates in java?
date-arithmetic, java
Solution
try the following
{
Date dt2 = new DateAndTime().getCurrentDateTime();
long diff = dt2.getTime() - dt1.getTime();
long diffSeconds = diff / 1000 % 60;
long diffMinutes = diff / (60 * 1000) % 60;
long diffHours = diff / (60 * 60 * 1000);
int diffInDays = (int) ((dt2.getTime() - dt1.getTime()) / (1000 * 60 * 60 * 24));
if (diffInDays > 1) {
System.err.println("Difference in number of days (2) : " + diffInDays);
return false;
} else if (diffHours > 24) {
System.err.println(">24");
return false;
} else if ((diffHours == 24) && (diffMinutes >= 1)) {
System.err.println("minutes");
return false;
}
return true;
}
Problem
I have two objects of DateTime, which need to find the duration of their difference, I have the following code but not sure how to continue it to get to the expected results as following: Example: ``` 11/03/14 09:30:58 11/03/14 09:33:43 elapsed time is 02 minutes and 45 seconds ----------------------------------------------------- 11/03/14 09:30:58 11/03/15 09:30:58 elapsed time is a day ----------------------------------------------------- 11/03/14 09:30:58 11/03/16 09:30:58 elapsed time is two days ----------------------------------------------------- 11/03/14 09:30:58 11/03/16 09:35:58 elapsed time is two days and 05 minutes ``` Code: ``` String dateStart = "11/03/14 09:29:58"; String dateStop = "11/03/14 09:33:43"; Custom date format SimpleDateFormat format = new SimpleDateFormat("yy/MM/dd HH:mm:ss"); Date d1 = null; Date d2 = null; try { d1 = format.parse(dateStart); d2 = format.parse(dateStop); } catch (ParseException e) { e.printStackTrace(); } // Get msec from each, and subtract. long diff = d2.getTime() - d1.getTime(); long diffSeconds = diff / 1000 % 60; long diffMinutes = diff / (60 * 1000) % 60; long diffHours = diff / (60 * 60 * 1000); System.out.println("Time in seconds: " + diffSeconds + " seconds."); System.out.println("Time in minutes: " + diffMinutes + " minutes."); System.out.println("Time in hours: " + diffHours + " hours."); ```