Why are JavaScript primitives not instanceof Object?
instanceof, javascript
Solution
You have been tricked by a mechanism commonly known as "boxing" (c# related article, java related article) which mesmerises all who come across it. You had the correct answer in the beginning:
Perhaps because 1 is a primitive not an object to begin with?
Exactly so. However, how can primitives ever be able to contain methods? How can they contain properties? After all, in js, they are represented at the lowest level possible (see #4.3.2). To make these values actually useful, whenever you do `primitive.property`, the following happens (#11.2.1):
Object(primitive).property;
In other words, js has automatic boxing. This can be proven using one of my favourite tricks:
var primitive = 'food';
primitive.isPizza = true; //yummy
console.log(primitive.isPizza); //undefined. where did my pizza go!?
`primitive.isPizza` disappeared because of this boxing:
var primitive = 'food';
Object(primitive).isPizza = true;
console.log(Object(primitive).isPizza);
The boxed `primitive` is its own unique snowflake - when you box it a second time, it does not refer to the same thing. The boxed values are quickly GCd and forgotten in the mists of time.
This does not happen if your primitive isn't, well, a primitive:
var obj = new String('food');
obj.isPizza = true;
console.log(obj.isPizza); //true
Does this mean you should only use objects, never primitives? Nope, for the simple reason that the times you do need to store meta-data on primitives are very far and few, and objects complicate things:
obj === primitive; //false, obj is an object, primitive is a primitive
Problem
Today I happened to have too much time to kill and I played a bit with the Node (v0.10.13) command line: ``` > 1 instanceof Object false > (1).__proto__ {} > (1).__proto__ instanceof Object true > (1).__proto__.__proto__ === Object.prototype true ``` Now, according to MDN, what `instanceof` does is: The instanceof operator tests whether an object has in its prototype chain the prototype property of a constructor. But clearly `Object.prototype` IS in `1`'s prototype chain. So why is `1 instanceof Object` false? Perhaps because `1` is a primitive not an object to begin with? Okay, I accept that, and I did more tests: ``` > (1).__proto__ === (2).__proto__ true > 'a'.__proto__ === 'b'.__proto__ true > (1).__proto__ === 'a'.__proto__ false > (1).__proto__.__proto__ === 'a'.__proto__.__proto__ true > (1).__proto__.type = 'number' 'number' > 'a'.__proto__.type = 'string' 'string' > (2).type 'number' > (1.5).type 'number' > 'b'.type 'string' ``` So apparently all number primitives inherit from one object, and all string primitives inherit from another object. Both these 2 objects inherit from `Object.prototype`. Now the question is, if numbers and strings are considered primitives, why inherit them from other objects? Or inversely, as they inherit from other objects, why not consider them objects too? It seems nonsensical to me that the child of an object isn't an object.. By the way, I have also tested these in Firefox 22 and got the same result.