Extract characters at a set position
r, string, truncate
Solution
If you know the exact position of the date in your string you can use
substr('LT50420331984221PAC00_B7.tif', 10, 16)
Problem
I am trying to find a function that will extract characters at a certain position within a string. For example, I have a long file name with a date in it, and I want to end up with only the date: ``` 'LT50420331984221PAC00_B7.tif' ``` and I want only the '1984221' portion. I've come up with a complicated function, but was wondering if there is a more elegant solution.