Why does os.path.isfile return False?

Question

``` >>> import os >>> os.listdir("/home/user/Desktop/1") ['1.txt', '2', '3.txt'] >>> os.path.isfile("/home/user/Desktop/1/1.txt") True >>> for i in os.listdir("/home/user/Desktop/1"): ... print(os.path.isfile(i)) ... False False False >>> ``` Two of them are files, why is the output `False` when it should be `True`?

Accepted Answer

When you print `os.path.isfile(i)`, you're checking if "1.txt" or "2" or "3.txt" is a file, whereas when you run `os.path.isfile("/home/user/Desktop/1/1.txt")` you have a full path to the file.

Try replacing that line with

```
print(os.path.isfile("/home/user/desktop/1/" + i))
```

Edit:

As mentioned in the comment below by icktoofay, a better solution might be to replace the line with

```
print(os.path.isfile(os.path.join("/home/user/desktop/1", i)))
```

or to earlier store "/home/user/desktop/1" to some variable x, allowing the line to be replaced with

```
print(os.path.isfile(os.path.join(x,i)))
```

Why does os.path.isfile return False?

Solution

Problem