python list group by first character

divide, python, python-itertools

Solution

You can use `itertools.groupby`:

>>> from itertools import groupby
>>> list1 = ['hello','hope','hate','hack','bit','basket','code','come','chess']
>>> [list(g) for k, g in groupby(list1, key=lambda x: x[0])]
[['hello', 'hope', 'hate', 'hack'], ['bit', 'basket'], ['code', 'come', 'chess']]

Problem

``` list1=['hello','hope','hate','hack','bit','basket','code','come','chess'] ``` What I need is: ``` list2=[['hello','hope','hate','hack'],['bit','basket'],['code','come','chess']] ``` If the first character is the same and is the same group, then sublist it. How can I solve this?

Original source