Joomla 3.0 MVC file upload in custom component backend
file-upload, joomla3.0, model-view-controller, php
Solution
Placing new field in database and XML form is only half of work. You also have to write file save/upload functionality. There are two places you can do it. In controller (for example save task procedure) or model (there are 2-3 functions where you can do it). Look into this file `/administrator/components/com_media/controllers/upload.php` (upload procedure). I would just extend your save function so before data will be saved into database file will be stored on file system. You can find original save function declaration in `/libraries/legacy/controller/legacy.php` (for Joomla 3.0.1, for other versions it shouldn't be hard to find)
Here is sample save function:
public function save($key = null, $urlVar = null){
// youre file upload code
return parent::save($key = null, $urlVar = null)
}
Problem
SOLUTION: How to Save Uploaded File's Name on Database this ended up helping me. i am trying to add a file upload to a custom component using XML and database. I know how to get file upload done in a static PHP environment but my knowledge about the PHP MVC structure in joomla makes it so I am unable to add it. What I have done so far: • Added the field in the XML file (of the type file) • Added the form fields in admin view project • Added an extra field My_project table(same as the image upload column) Until this point it works.(fields are shown in admin backend component) Now when you save the document with a file uploaded in the admin back end it does not save it to the database. if i put media as field type then it works, but when i change it to file it breaks down. XML file ``` <?xml version="1.0" encoding="utf-8"?> <form> <fieldset> <field name="project_file" type="file" label="Upload file" description="Upload file" directory="mysites" /> <field name="main_image" type="media" label="COM_MYSITES_FORM_LBL_PROJECT_MAIN_IMAGE" description="COM_MYSITES_FORM_DESC_PROJECT_MAIN_IMAGE" filter="raw" directory="mysites" /> </fieldset> ``` PHP file upload script i normaly use ``` <?php $temp = explode(".", $_FILES["file"]["name"]); $extension = end($temp); if ($_FILES["file"]["error"] > 0) { echo "Return Code: " . $_FILES["file"]["error"] . "<br>"; } else { echo "Upload: " . $_FILES["file"]["name"] . "<br>"; echo "Type: " . $_FILES["file"]["type"] . "<br>"; echo "Size: " . ($_FILES["file"]["size"] / 1024) . " kB<br>"; echo "Temp file: " . $_FILES["file"]["tmp_name"] . "<br>"; if (file_exists("upload/" . $_FILES["file"]["name"])) { echo $_FILES["file"]["name"] . " already exists. "; } else { move_uploaded_file($_FILES["file"]["tmp_name"], "upload/" . $_FILES["file"]["name"]); echo "Stored in: " . "upload/" . $_FILES["file"]["name"]; } } } else { echo "Invalid file"; } ?> ``` but what part goes in the model and what part goes in the controller? and how to call it. entire view is called in the controller ``` class MysitesControllerProject extends JControllerForm { function __construct() { $this->view_list = 'projects'; $jinput = JFactory::getApplication()->input; $files = $jinput->files->get('jform'); $file = $files['project_file']; $this->upload($file); parent::__construct(); } public function upload($files) { $file_name = $files['name']; $src = $files['tmp_name']; $size = $files['size']; $upload_error = $files['error']; $type = $files['type']; $dest = "/home/vol3/byethost33.com/b33_13467508/bim-portfolio.cu.cc/htdocs/tmp"; if (isset( $file_name)) { // Move the uploaded file. JFile::upload( $src, $filepath ); } } } ```