Unwind Segue Programmatically - New twist

Context: I have two VC, A and B. VC A contains several buttons and several labels. When pressing the button in VC A a segue will display VC B/C/ and so forth. Now, when finished with VC A/B/C so forth, the segue is being unwind so that VC A appears. For most of the VC B/C/D so forth, I am using the unwind method which I trigger through a button in that VC (ctrl + drag to "exit" icon). This works perfect, because upon returning to VC A, the following action is being called automatically: ``` - (IBAction)returned:(UIStoryboardSegue *)segue { // Here I do some stuff } ``` Problem: Now, in one of the secondary VCs (e.g. D), things are a bit special. In this VC I generate some hundred buttons through a loop programmatically, then detect which button is being pressed and finally unwind back to VC A (without a specific button; any of the buttons will trigger the unwind). I know I can do this eg by using this ``` [self dismissViewControllerAnimated: YES completion: nil] ``` but this does not trigger the above action when returning to VC A, or by using this ``` [self performSegueWithIdentifier:@"UnwindSegueIdentifier" sender:self] ``` but this will generate a new instance of VC A, which I do not want (because labels in the instance of VC A already contains some information). So, what I want is to be able to return to the same instance of VC A which generated the VC D, and also trigger the "returned" action listed above. Thus, I want to achieve the same effect as when using a button connected to the "exit" icon, but I want to do this programmatically "inside the code" when one the many buttons in VC D is pressed. Any thoughts?