How to catch an Exception like this on Flask?

flask, python, try-catch

Solution

I recently ran into this error message while trying to use Flask to serve audio files. I get this error message whenever the client closes the stream before the end of the stream.

This error message doesn't originate from your Flask application, but rather from the underlying SocketServer used to dispatch request data. What is happening is the connection to the client is ending for some reason, but Flask continues to try to write data to the closed socket. You can't catch this exception from your Flask application, because Flask catches it for you. Flask prints it out as a service to you, notifying you that the stream was closed prematurely, i.e. before Flask finished writing data to the stream.

To sum it up, this error message is internal to Flask, Flask is printing it to tell you that it couldn't get all the data to the client before the connection closed. You can't catch it, and you shouldn't have any reason to catch it.

Problem

I run a simple flask app like this: ``` from flask import Flask app = Flask(__name__) @app.route('/') def welcome(): return "OK" app.config.update( DEBUG = True ) if __name__ == '__main__': app.run(use_reloader = False) ``` when I run it and visit it, sometimes(not always) it could't response the request and throw an except: ``` Exception happened during processing of request from ('127.0.0.1', 54481) Traceback (most recent call last): File "c:\python27\Lib\SocketServer.py", line 295, in _handle_request_noblock self.process_request(request, client_address) File "c:\python27\Lib\SocketServer.py", line 321, in process_request self.finish_request(request, client_address) File "c:\python27\Lib\SocketServer.py", line 334, in finish_request self.RequestHandlerClass(request, client_address, self) File "c:\python27\Lib\SocketServer.py", line 651, in __init__ self.finish() File "c:\python27\Lib\SocketServer.py", line 710, in finish self.wfile.close() File "c:\python27\Lib\socket.py", line 279, in close self.flush() File "c:\python27\Lib\socket.py", line 303, in flush self._sock.sendall(view[write_offset:write_offset+buffer_size]) error: [Errno 10053] ``` I can't understand what cause this fault? and how can I solve it? and how can I use `try except` to catch it?

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