How to use sed to return something from first line which matches and quit early?
sed
Solution
My specific use case was to find out via 'git log' on a git-p4 imported tree which perforce branch was used for the last commit. git log (when called without -n will log every commit that every happened (hundreds of thousands for me)).
We can't know a-priori what value to give git for '-n.' After posting this, I found my solution which was:
git log | sed -n '0,/.*\[git-p4:.*\/\/depot\/blah\/\([^\/]*\)\/.*/s//\1/p; /\[git-p4/ q'
I'd still like to know how to do this with a non '/' separator, and without having to specify the 'git-p4' part twice, once for the extraction and once for the quit. There has got to be a way to combine both on the same line...
Problem
I saw from How to use sed to replace only the first occurrence in a file? How to do most of what I want: ``` sed -n '0,/.*\(something\).*/s//\1/p' ``` This finds the first match of something and extracts it (of course my real example is more complicated). I know sed has a 'quit' command which will make it stop early, but I don't know how to combine the 'q' with the above line to get my desired behavior. I've tried replacing the 'p' with {p;q;} as I've seen in some examples, but that is clearly not working.