How to extract file from zip without maintaining directory structure in Python?

directory-structure, python, unzip, zip

Solution

You can use zipfile.ZipFile.open:

import shutil
import zipfile

with zipfile.ZipFile('/path/to/my_file.apk') as z:
    with z.open('/res/drawable/icon.png') as zf, open('temp/icon.png', 'wb') as f:
        shutil.copyfileobj(zf, f)

Or use zipfile.ZipFile.read:

import zipfile

with zipfile.ZipFile('/path/to/my_file.apk') as z:
    with open('temp/icon.png', 'wb') as f:
        f.write(z.read('/res/drawable/icon.png'))

Problem

I'm trying to extract a specific file from a zip archive using python. In this case, extract an apk's icon from the apk itself. I am currently using ``` with zipfile.ZipFile('/path/to/my_file.apk') as z: # extract /res/drawable/icon.png from apk to /temp/... z.extract('/res/drawable/icon.png', 'temp/') ``` which does work, in my script directory it's creating `temp/res/drawable/icon.png` which is temp plus the same path as the file is inside the apk. What I actually want is to end up with `temp/icon.png`. Is there any way of doing this directly with a zip command, or do I need to extract, then move the file, then remove the directories manually?

Original source