Printf and hex values
c, c++, formatting, printf, string
Solution
My guess is that `value` is 8. :-)
Are you on a little endian machine, such as x86? I'm going to guess that by `be16` you mean that the value is big endian and you need to swap the bytes.
Problem
So, I have a value of type __be16 (2 bytes). In hex, the value is represented as 0x0800 or 2048 in decimal. (16^2 * 8) So, when I printf this; I do this: ``` printf("%04X", value); //__be16 value; //Print a hex value of at least 4 characters, no padding. ``` output: 0008 ``` printf("%i", value); //Print an integer. ``` output: 8 I should be getting 0800 and 2048 respectively, what am I doing wrong?