C++ bool array as bitfield?
bit-fields, boolean, c++, struct
Solution
I would recommend using a `std::bitset` That way you could simply declare:
std::bitset<8> asdf;
and use it with [].
asdf[0] = true;
asdf[3] = false;
Problem
let's say i need to store 8 bools in a struct, but i want to use for them only 1 byte together, then i could do something like this: ``` struct myStruct { bool b1:1; bool b2:1; bool b3:1; bool b4:1; bool b5:1; bool b6:1; bool b7:1; bool b8:1; }; ``` and with this i could do things like ``` myStruct asdf; asdf.b3=true; asdf.b4=false; if(asdf.b1) ... ``` is this correct so far? (i don't know it actually, i never used bitfields before) ok - but is it also possible to create a static array of 8 bools such that they will use only 8 bits but i will still be able to adress them by index? something like ``` struct myStruct { public: bool b[8]:8; }; ``` maybe? (with this, i get a error C2033) thanks for the help!