Get java version from batch file

Question

How to get java version and want to get '6' out of java version from batch file. I tried below script, but it didn't work. ``` REM check java exists using JAVA_HOME system variable if "%JAVA_HOME%" == "" ( ECHO Installing java start /w jdk.exe /s SETX -m JAVA_HOME "C:\Program Files\Java\jdk1.6.0_31" ECHO java installed successfully ) ELSE ( ECHO checking java version goto check_java_version ) REM check java version using JAVA_HOME system variable :check_java_version set PATH=%PATH%;%JAVA_HOME%\bin for /f tokens^=2-5^ delims^=.-_^" %%j in ('%JAVA_HOME%/bin/java -version 2^>^&1') do set "jver=%%j%%k%%l%%m" echo %jver% ``` JAVA_HOME has "C:\Program Files\Java\jdk1.6.0_31" value.

Accepted Answer

```
for /f tokens^=2-5^ delims^=.-_^" %j in ('java -fullversion 2^>^&1') do @set "jver=%j%k%l%m"
```

This will store the java version into `jver` variable and as integer And you can use it for comparisons .E.G

```
if %jver% LSS 16000 echo not supported version
```

.You can use more major version by removing %k and %l and %m.This command prompt version.

For .bat use this:

```
@echo off
PATH %PATH%;%JAVA_HOME%\bin\
for /f tokens^=2-5^ delims^=.-_^" %%j in ('java -fullversion 2^>^&1') do set "jver=%%j%%k%%l%%m"
```

According to my tests this is the fastest way to get the java version from bat (as it uses only internal commands and not external ones as `FIND`,`FINDSTR` and does not use `GOTO` which also can slow the script). Some JDK vendors does not support `-fullversion` switch or their implementation is not the same as this one provided by Oracle (better avoid them).

Get java version from batch file

Solution

Problem