What's the output of the following code?
c++, struct
Solution
`i(x);` is equivalent to `i x;`, with a redundant pair of parentheses thrown in. It declares a variable named `x` of type `i`, default-initialized; it does not create a temporary instance of `i` with `x` as the constructor's parameter. See also: most vexing parse
Problem
This code was published in http://accu.org/index.php/cvujournal, Issue July 2013. I couldn't comprehend the output, any explanation would be helphful ``` #include <iostream> int x; struct i { i() { x = 0; std::cout << "--C1\n"; } i(int i) { x = i; std::cout << "--C2\n"; } }; class l { public: l(int i) : x(i) {} void load() { i(x); } private: int x; }; int main() { l l(42); l.load(); std::cout << x << std::endl; } ``` Output: ``` --C1 0 ``` I was expecting: ``` --C2 42 ``` Any Explanation ?