Extract a part of URL - python

python, python-2.7, regex, url

Solution

In this specific example splitting the string is enough:

url.split('/')[-1]

If you have a more complex URL I would recommend the yarl library for parsing it:

>>> import yarl  # pip install yarl
>>> url = yarl.URL('http://name.abc.wxyz:1234/Assts/asset.epx?id=F3F94D94-7232-4FA2-98EF-07sdfssfdsa3B5')
>>> url.path_qs
'/Assts/asset.epx?id=F3F94D94-7232-4FA2-98EF-07sdfssfdsa3B5'

You could also use the builtin `urllib.parse` library but I find that it gets in the way once you start doing complex things like:

>>> url.update_query(asd='foo').with_fragment('asd/foo/bar')
URL('http://name.abc.wxyz:1234/Assts/asset.epx?id=F3F94D94-7232-4FA2-98EF-07sdfssfdsa3B5&asd=foo#asd/foo/bar')

Problem

I have an URL for example: ``` http://name.abc.wxyz:1234/Assts/asset.epx?id=F3F94D94-7232-4FA2-98EF-07sdfssfdsa3B5 ``` From this Url I want to extract only '`asset.epx?id=F3F94D94-7232-4FA2-98EF-07sdfssfdsa3B5`' how could i do that? I am still learning regular expressions and I am not able to solve the above. Any suggestions would be appreciated.

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