Python: testing for utf-8 character in string
python, right-to-left, unicode
Solution
Every unicode character has a "bidirectional" class. You can find the bidirectional class using unicodedata.bidirectional. The function returns a string, e.g. 'L', 'R', 'AL', etc. with the following meaning:
| L | Left_To_Right | any strong left-to-right character |
| LRE | Left_To_Right_Embedding | U+202A: the LR embedding control |
| LRO | Left_To_Right_Override | U+202D: the LR override control |
| R | Right_To_Left | any strong right-to-left (non-Arabic-type) character |
| AL | Arabic_Letter | any strong right-to-left (Arabic-type) character |
| RLE | Right_To_Left_Embedding | U+202B: the RL embedding control |
| RLO | Right_To_Left_Override | U+202E: the RL override control |
| PDF | Pop_Directional_Format | U+202C: terminates an embedding or override control |
| EN | European_Number | any ASCII digit or Eastern Arabic-Indic digit |
| ES | European_Separator | plus and minus signs |
| ET | European_Terminator | a terminator in a numeric format context, includes currency signs |
| AN | Arabic_Number | any Arabic-Indic digit |
| CS | Common_Separator | commas, colons, and slashes |
| NSM | Nonspacing_Mark | any nonspacing mark |
| BN | Boundary_Neutral | most format characters, control codes, or noncharacters |
| B | Paragraph_Separator | various newline characters |
| S | Segment_Separator | various segment-related control codes |
| WS | White_Space | spaces |
| ON | Other_Neutral | most other symbols and punctuation marks |
For instance:
In [3]: import unicodedata as UD
In [5]: UD.bidirectional(u'\u0688')
Out[5]: 'AL'
In [6]: UD.bidirectional(u'\u200f')
Out[6]: 'R'
In [7]: UD.bidirectional(u'H')
Out[7]: 'L'
So you might be able to guess if a string is right-to-left by determining if it is composed mainly of characters whose bidirectional class is `R` or `AL`.
For example,
# coding: utf-8
import unicodedata as UD
texts = ['ڈوگرى'.decode('utf-8'),
u'Hello']
for text in texts:
x = len([None for ch in text if UD.bidirectional(ch) in ('R', 'AL')])/float(len(text))
print('{t} => {c}'.format(t=text.encode('utf-8'), c='RTL' if x>0.5 else 'LTR'))
yields
ڈوگرى => RTL
Hello => LTR
Regarding the first question:
Q: What is the correct syntax to test for the occurrence of a single non-ASCII character in a string? Python 2.6 and I can't use 3.
Your method for testing if a character is in a `unicode` is correct. If `u'\u200f' in str.decode('utf-8')` neither complains nor works, then `u'\u200f'` is not in the `unicode`.
Problem
I need to test whether a string that has already been encoded with str.encode('utf-8') is right-to-left. I tried ``` if u'\u200f' in str.decode('utf-8'): print 'found it' ``` It neither complains nor works. Q: What is the correct syntax to test for the occurrence of a single non-ASCII character in a string? Python 2.6 and I can't use 3. Q: I remember reading that predominantly right-to-left characters default to RTL even without an explicit RML. Does anyone know a way to test such a string without knowing which language to expect (i.e. the string can be in Arabic, Hebrew or any other RTL language)? Thanks for all help.