why can't we assign weaker privilege in subclass

inheritance, java

Solution

The short answer is that it is not allowed because it would break type substitutability; see also the Liskov Substititution Principle (LSP).

The point is that polymorphism in Java (and other programming languages) relies on you being able to treat an instance of a subclass as if it was an instance of the superclass. But if the method is restricted in the subclass, you find that the compiler cannot figure out whether the access rules allow a method to be called ...

For instance, lets assume that your example code was legal:

// Assume this code is in some other class ...

SuperClass s1 = new SuperClass();

s1.foo();                          // OK!

SuperClass s2 = new Subclass();

s2.foo();                          // What happens now?

SuperClass s3 = OtherClass.someMethod();

s3.foo();                          // What happens now?

If you base the decision on whether `s2.foo()` is allowed on the declared type of `s2`, then you allow a call to a `private` method from outside the abstraction boundary of `Subclass`.

If you base the decision on the actual type of the object that `s2` refers to, you cannot do the access check statically. The `s3` case makes this even clearer. The compiler has absolutely no way of knowing what the actual type of the object returned by `someMethod` will be.

Access checks that could result in runtime exceptions would be a major source of bugs in Java application. The language restriction under discussion here avoids this nasty problem.

Problem

I have a class which has a method whose access specifier by default is public. Now, I would like to extend this class in a subclass and I want to override this method to have access specifier "private". When compiling this code, I am getting a compilation error: "attempting to assign weaker access privileges". Could somebody please explain to me what is wrong with assigning weaker privileges in a subclass? Here is the code that caused the compilation error: ``` class Superclass { void foo() { System.out.println("Superclass.foo"); } } class Subclass extends Superclass { private void foo() { System.out.println("Subclass.foo"); } } ```

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