greater than 'date' python 3
python, python-3.x
Solution
You can use the `datetime` module to convert them all to datetime objects. You are comparing strings in your example:
>>> from datetime import datetime
>>> date1 = datetime.strptime(date1, "%d/%m/%Y")
>>> date2 = datetime.strptime(date2, "%d/%m/%Y")
>>> date3 = datetime.strptime(date3, "%d/%m/%Y")
>>> date4 = datetime.strptime(date4, "%d/%m/%Y")
>>> datelist = [date1, date2, date3]
>>> for j in datelist:
... if j <= date4:
... print(j.strftime('%d/%m/%Y'))
...
20/06/2013
25/06/2013
01/07/2013
Problem
I would like to be able to do greater than and less than against dates. How would I go about doing that? For example: ``` date1 = "20/06/2013" date2 = "25/06/2013" date3 = "01/07/2013" date4 = "07/07/2013" datelist = [date1, date2, date3] for j in datelist: if j <= date4: print j ``` If I run the above, I get date3 back and not date1 or date2. I think I need I need to get the system to realise it's a date and I don't know how to do that. Can someone lend a hand? Thanks