Iterate over two arrays simultaneously in bash
arrays, bash, loops
Solution
From anishsane's answer and the comments therein we now know what you want. Here's the same thing in a bashier style, using a for loop. See the Looping Constructs section in the reference manual. I'm also using `printf` instead of `echo`.
#!/bin/bash
array=( "Vietnam" "Germany" "Argentina" )
array2=( "Asia" "Europe" "America" )
for i in "${!array[@]}"; do
printf "%s is in %s\n" "${array[i]}" "${array2[i]}"
done
Another possibility would be to use an associative array:
#!/bin/bash
declare -A continent
continent[Vietnam]=Asia
continent[Germany]=Europe
continent[Argentina]=America
for c in "${!continent[@]}"; do
printf "%s is in %s\n" "$c" "${continent[$c]}"
done
Depending on what you want to do, you might as well consider this second possibility. But note that you won't easily have control on the order the fields are shown in the second possibility (well, it's an associative array, so it's not really a surprise).
Problem
I have two arrays. ``` array=( Vietnam Germany Argentina ) array2=( Asia Europe America ) ``` I want to loop over these two arrays simulataneously, i.e. invoke a command on the first elements of the two arrays, then invoke the same command on the second elements, and so on. Pseudocode: ``` for c in ${array[*]} do echo -e " $c is in ......" done ``` How can I do this?