C++ Passing array into function

arrays, c++, function, parameter-passing

Solution

You are passing a copy of the array, so any changes will not affect the original. Pass by reference instead:

void addToArray(Array<int> &intarray)
//                         ^

Problem

I'm relatively new to C++ and am having a tough time passing my array into a separate function. Apologies for re-asking a question that has no doubt been answered a dozen times before, but I couldn't find any questions similar to the problem I have with my code. ``` int main() { Array<int> intarray(10); int grow_size = 0; intarray[0] = 42; intarray[1] = 12; intarray[9] = 88; intarray.Resize(intarray.Size()+2); intarray.Insert(10, 6); addToArray(intarray); int i = intarray[0]; for (i=0;i<intarray.Size();i++) cout<<i<<'\t'<<intarray[i]<<endl; Sleep(5000); } void addToArray(Array<int> intarray) { int newValue; int newIndex; cout<<"What do you want to add to the array?"<<endl; cin >> newValue; cout<<"At what point should this value be added?"<<endl; cin >> newIndex; intarray.Insert(newValue, newIndex); } ```

Original source