Why can't I pass a block to the proc in Ruby?
proc, ruby
Solution
`yield` applies to the block passed to the wrapping method context. In your case, I presume it is whichever method `irb` relies upon (`lib/ruby/2.0.0/irb/workspace.rb:86 evaluate`, if `caller` is anything to go by).
If you wrap it in a function it'll work, because you change the method context:
def do_stuff
do_once = Proc.new { yield }
do_once.call
end
do_stuff { puts 1 }
Note the absence of block for `do_once.call` in the above: `yield` applies to the block passed to `do_stuff`, rather than to the block passed to `do_once`.
Alternatively, declare the block explicitly to avoid the use of yield altogether:
do_once = Proc.new { |&block| block.call }
do_once.call { puts 1 }
Problem
Why can't I do something like this: ``` do_once = Proc.new { yield } do_once.call { puts 1 } ``` irb throws `LocalJumpError: no block given (yield)`