Remove item from array if it exists in a 'disallowed words' array
arrays, php
Solution
You want `array_diff`.
`array_diff` returns an array containing all the entries from `array1` that are not present in any of the other arrays.
So you want something like:
$good = array_diff($arr, $disallowed_words);
Problem
I have an array: ``` Array ( [0] => tom [1] => and [2] => jerry ) ``` And I also have a disallowed words array: ``` Array ( [0] => and [1] => foo [2] => bar ) ``` What I need to do is remove any item in the first array that also appears in the second array, in this instance for example, key 1 would need to be removed, as 'and' is in the disallowed words array. Now I currently have this code, which does a foreach on the disallowed words and then uses array_search to find any matches: ``` $arr=array('tom','and','jerry'); $disallowed_words=array('and','or','if'); foreach($disallowed_words as $key => $value) { $arr_key=array_search($value,$array); if($arr_key!='') { unset($search_terms[$arr_key]); } } ``` Now I know this code sucks, what I want to know is if there is a more efficient method of removing and item from an array where it exists in another array, especially if it negates using a foreach.