How to get UITouch location from UIGestureRecognizer

cocos2d-iphone, ios, objective-c, uigesturerecognizer, xcode

Solution

You can use the `locationInView:` method on UIGestureRecognizer. If you pass nil for the view, this method will return the location of the touch in the window.

- (void)handleTap:(UITapGestureRecognizer *)tapRecognizer
{
    CGPoint touchPoint = [tapRecognizer locationInView: _tileMap]
}

There is also a helpful delegate method `gestureRecognizer:shouldReceiveTouch:`. Just make sure to implement and set your tap gesture's delegate to self.

Keep a reference to the gesture recognizer.

@property UITapGestureRecognizer *theTapRecognizer;

Initiailze the gesture recognizer

_theTapRecognizer = [[UITapGestureRecognizer alloc] initWithTarget: self action: @selector(someMethod:)];
_theTapRecognizer.delegate = self;
[someView addGestureRecognizer: _theTapRecognizer];

Listen for delegate methods.

-(BOOL)gestureRecognizer:(UIGestureRecognizer *)gestureRecognizer shouldReceiveTouch:(UITouch *)touch
{
    CGPoint touchLocation = [_tileMap convertTouchToNodeSpace: touch];
    // use your CGPoint
    return YES;
}

Problem

I want to get the UITouch location of my tap from UIGestureRecognizer, but I can not figure out how to from looking at both the documentation and other SO questions. Can one of you guide me? ``` - (void)handleTap:(UITapGestureRecognizer *)tapRecognizer { CCLOG(@"Single tap"); UITouch *locationOfTap = tapRecognizer; //This doesn't work CGPoint touchLocation = [_tileMap convertTouchToNodeSpace:locationOfTap]; //convertTouchToNodeSpace requires UITouch [_cat moveToward:touchLocation]; } ``` FIXED CODE HERE - THIS ALSO FIXES INVERTED Y AXIS ``` CGPoint touchLocation = [[CCDirector sharedDirector] convertToGL:[self convertToNodeSpace:[tapRecognizer locationInView:[[CCDirector sharedDirector] openGLView]]]]; ```

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