How to Convert Nested List into dictionary in Python where lst[0][0] is the key
dictionary, list, python, python-3.x
Solution
If I understand you correctly, I think you're after the following.
You can use a dict-comp for versions 2.7+:
{ k[0]: k[1:] for k in lst }
Prior to 2.7 (2.6 and below), this would have been done using the `dict` builtin, eg:
dict( (k[0], k[1:]) for k in lst)
# {'kataba': ['V:', '3rd_sg_masc_perf_active'], 'katabat': ['V:', '3rd_sg_fm_perf_active'], 'katabata:': ['V:', '3rd_dual_fm_perf_active'], 'katabu:': ['V:', '3rd_pl_masc_perf_active'], 'kataba:': ['V:', '3rd_dual_masc_perf_active']}
Problem
I have a `Python 3.x` nested list that looks like the following: ``` lst = [['kataba', 'V:', '3rd_sg_masc_perf_active'], ['kataba:', 'V:', '3rd_dual_masc_perf_active'], ['katabu:', 'V:', '3rd_pl_masc_perf_active'], ['katabat', 'V:', '3rd_sg_fm_perf_active'], ['katabata:', 'V:', '3rd_dual_fm_perf_active']] ``` I will slice one instance so that my question will be clearer ``` >>> lst[0] ['kataba', 'V:', '3rd_sg_masc_perf_active'] >>> lst[0][0] 'kataba' >>> lst[0][1:] ['V:', '3rd_sg_masc_perf_active'] ``` How to convert the above nested list into a dictionary where, for example, lst[0][0] will be the dictionary key, and lst[0][1:] will be the value of the key. This nested list contains tens of thousands of elements. Could you help me, because I have tried many options but it seems that I don't have the logic to do it.