Create a black and white chessboard in a two dimensional array
python
Solution
How about:
>>> n = 3
>>> board = [["BW"[(i+j+n%2+1) % 2] for i in range(n)] for j in range(n)]
>>> print board
[['B', 'W', 'B'], ['W', 'B', 'W'], ['B', 'W', 'B']]
>>> n = 4
>>> board = [["BW"[(i+j+n%2+1) % 2] for i in range(n)] for j in range(n)]
>>> print board
[['W', 'B', 'W', 'B'], ['B', 'W', 'B', 'W'], ['W', 'B', 'W', 'B'], ['B', 'W', 'B', 'W']]
Problem
Is there a better (and shorter) way of how to create chessboard like array. Requirements for the board are: - board can be different size (in my example it's 3x3) - bottom left square of the board should always be black - black square is presented by `"B"`, white square is presented by `"W"` Code that I have: ``` def isEven(number): return number % 2 == 0 board = [["B" for x in range(3)] for x in range(3)] if isEven(len(board)): for rowIndex, row in enumerate(board): if isEven(rowIndex + 1): for squareIndex, square in enumerate(row): if isEven(squareIndex + 1): board[rowIndex][squareIndex] = "W" else: for squareIndex, square in enumerate(row): if not isEven(squareIndex + 1): board[rowIndex][squareIndex] = "W" else: for rowIndex, row in enumerate(board): if not isEven(rowIndex + 1): for squareIndex, square in enumerate(row): if isEven(squareIndex + 1): board[rowIndex][squareIndex] = "W" else: for squareIndex, square in enumerate(row): if not isEven(squareIndex + 1): board[rowIndex][squareIndex] = "W" for row in board: print row ``` Output: ``` ['B', 'W', 'B'] ['W', 'B', 'W'] ['B', 'W', 'B'] ```