Extracting sub-string after the first space in Python
python, regex
Solution
I recommend using `split`
>>> s="A:01 What is the date of the election ?"
>>> " ".join(s.split()[1:-1])
'What is the date of the election'
>>> s="BK:02 How long is the river Nile ?"
>>> " ".join(s.split()[1:-1])
'How long is the river Nile'
>>> s="Date:30/4/2013"
>>> s.split(":")[1:][0]
'30/4/2013'
>>> s="Day:Tuesday"
>>> s.split(":")[1:][0]
'Tuesday'
Problem
I need help in regex or Python to extract a substring from a set of string. The string consists of alphanumeric. I just want the substring that starts after the first space and ends before the last space like the example given below. ``` Example 1: A:01 What is the date of the election ? BK:02 How long is the river Nile ? Results: What is the date of the election How long is the river Nile ``` While I am at it, is there an easy way to extract strings before or after a certain character? For example, I want to extract the date or day like from a string like the ones given in Example 2. ``` Example 2: Date:30/4/2013 Day:Tuesday Results: 30/4/2013 Tuesday ``` I have actually read about regex but it's very alien to me. Thanks.