t-SQL to find Top 10 Records for Each Group
row-number, sql, subquery, t-sql
Solution
I think you're looking for `ROW_NUMBER()` with a `PARTITION BY`
SELECT *
FROM (
SELECT
ROW_NUMBER() OVER(PARTITION BY t.TranSID ORDER BY t.TranSID, SUM(IIF(TranTypeID = 'CO', td.Qty * CAST(td.Price AS money) * - 1, td.Qty * CAST(td.Price AS money))) DESC) as RowNum,
a.ABID,
a.ABName,
t.TranSID,
SUM(IIF(TranTypeID = 'CO', td.Qty * CAST(td.Price AS money) * - 1, td.Qty * CAST(td.Price AS money))) AS TotalSales
FROM Trans t
INNER JOIN TransDetail td
ON t.TranID = td.TranID
INNER JOIN ABook a
ON t.TranABID = a.ABID
WHERE (t.TranDate BETWEEN CONVERT(DATETIME, '2012-01-01 00:00:00', 102) AND CONVERT(DATETIME, '2013-01-01 00:00:00', 102))
AND t.TranTypeID in ('SO','CA','CO')
AND (t.TranStatus <> 'V')
GROUP BY a.ABID, a.ABName, t.TranSID
HAVING (NOT (a.ABName LIKE '%cash%'))
) a
WHERE a.RowNum <=10
This will assign a row number to each record in the grouping (the column defined by the `PARTITION`, going from 1 to n. From there, you can run a `SELECT` on it to grab any number of records per group.
Problem
I am trying to figure out how to return the top 10 records for each group of Trans.TranSID. ``` SELECT a.ABID, a.ABName, t.TranSID, SUM(IIF(TranTypeID = 'CO', td.Qty * CAST(td.Price AS money) * - 1, td.Qty * CAST(td.Price AS money))) AS TotalSales FROM Trans t INNER JOIN TransDetail td ON t.TranID = td.TranID INNER JOIN ABook a ON t.TranABID = a.ABID WHERE (t.TranDate BETWEEN CONVERT(DATETIME, '2012-01-01 00:00:00', 102) AND CONVERT(DATETIME, '2013-01-01 00:00:00', 102)) AND t.TranTypeID in ('SO','CA','CO') AND (t.TranStatus <> 'V') GROUP BY a.ABID, a.ABName, t.TranSID HAVING (NOT (a.ABName LIKE '%cash%')) ORDER BY t.TranSID, TotalSales Desc ``` I can add "TOP 10" to the select statement, but that gives me the top 10 accounts regardless of the group. There are 25 groups of Trans.TranSID and I'm trying to get the top 10 only for each group.