subprocess.call does not wait for the process to complete
python, subprocess
Solution
The problem is that the `soffice` command-line tool (which `libreoffice` is either just a link to, or a further wrapper around) is just a "controller" for the real program `soffice.bin`. It finds a running copy of `soffice.bin` and/or creates on, tells it to do some work, and then quits.
So, `call` is doing exactly the right thing: it waits for `libreoffice` to quit.
But you don't want to wait for `libreoffice` to quit, you want to wait for `soffice.bin` to finish doing the work that `libreoffice` asked it to do.
It looks like what you're trying to do isn't possible to do directly. But it's possible to do indirectly.
The docs say that headless mode:
… allows using the application without user interface.
This special mode can be used when the application is controlled by external clients via the API.
In other words, the app doesn't quit after running some UNO strings/doing some conversions/whatever else you specify on the command line, it sits around waiting for more UNO commands from outside, while the launcher just runs as soon as it sends the appropriate commands to the app.
You probably have to use that above-mentioned external control API (UNO) directly.
See Scripting LibreOffice for the basics (although there's more info there about internal scripting than external), and the API documentation for details and examples.
But there may be an even simpler answer: `unoconv` is a simple command-line tool written using the UNO API that does exactly what you want. It starts up LibreOffice if necessary, sends it some commands, waits for the results, and then quits. So if you just use `unoconv` instead of `libreoffice`, `call` is all you need.
Also notice that `unoconv` is written in Python, and is designed to be used as a module. If you just `import` it, you can write your own (simpler, and use-case-specific) code to replace the "Main entrance" code, and not use `subprocess` at all. (Or, of course, you can tear apart the module and use the relevant code yourself, or just use it as a very nice piece of sample code for using UNO from Python.)
Also, the `unoconv` page linked above lists a variety of other similar tools, some that work via UNO and some that don't, so if it doesn't work for you, try the others.
If nothing else works, you could consider, e.g., creating a sentinel file and using a filesystem watch, so at least you'll be able to detect exactly when it's finished its work, instead of having to guess at a timeout. But that's a real last-ditch workaround that you shouldn't even consider until eliminating all of the other options.
Problem
Per Python documentation, `subprocess.call` should be blocking and wait for the subprocess to complete. In this code I am trying to convert few `xls` files to a new format by calling `Libreoffice` on command line. I assumed that the call to subprocess call is blocking but seems like I need to add an artificial delay after each call otherwise I miss few files in the `out` directory. what am I doing wrong? and why do I need the delay? ``` from subprocess import call for i in range(0,len(sorted_files)): args = ['libreoffice', '-headless', '-convert-to', 'xls', "%s/%s.xls" %(sorted_files[i]['filename'],sorted_files[i]['filename']), '-outdir', 'out'] call(args) var = raw_input("Enter something: ") # if comment this line I dont get all the files in out directory ``` EDIT It might be hard to find the answer through the comments below. I used `unoconv` for document conversion which is blocking and easy to work with from an script.