Call base class method when derived class overloads it

class, overloading, python

Solution

Like this:

class A(object):
    def x(self): print "Hello"
    def y(self): A.x(self)

...although that's slightly weird. Why are you (or, why is someone) overriding `x` if you don't want it called in this situation?

If you don't want it overridden, give it a double-underscore prefix:

class A(object):
    def __x(self): print "Hello"
    def y(self): self.__x()

Anyone defining `__x` in a derived class will get their own unique `__x` that doesn't override yours - see Private Variables and Class-local References.

Problem

I have the following: ``` class A(object): def x(self): print "Hello" def y(self): self.x() class Abis(A): def x(self): print "Bye" a = Abis() a.x() a.y() ``` Which prints: ``` Bye Bye ``` But I actually wanted: ``` Bye Hello ``` Since I want `A.y` to call the "original" `A.x`. How can I reference the original `A.x` in `A`, when the derived class has overloaded it?

Original source