Trying to create a REst Service using Jersey

java, jersey, maven, rest

Solution

The property `com.sun.jersey.config.property.package` just needs to be set as the package that contains the web service classes. In the tutorial it is `de.vogella.jersey.first`, and you can see that the `Hello` class is declared under that package.

In other words, when you deploy the application, Jersey will look for web service classes in the package `de.vogella.jersey.first`, and in this case it will find the class `Hello` being declared with the `javax.ws.rs.Path` annotation, and create a web service endpoint listening on the URL that has been declared with `@Path`.

However, I have never set such a thing for my Jersey projects. I just put my web service classes in the `src` folder, and Jersey recognizes them no matter which package I put them inside. This is the minimum configuration that I have with Jersey projects in `web.xml`:

<servlet>
    <description>JAX-RS Tools Generated - Do not modify</description>
    <servlet-name>JAX-RS Servlet</servlet-name>
    <servlet-class>com.sun.jersey.spi.container.servlet.ServletContainer</servlet-class>

    <!-- 
    <init-param>
        <param-name>com.sun.jersey.config.property.packages</param-name>
        <param-value>com.your.webservice.classes</param-value>
    </init-param> 
    -->

    <load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
    <servlet-name>JAX-RS Servlet</servlet-name>
    <url-pattern>/*</url-pattern>
</servlet-mapping>

Also if you do not fancy Maven projects, just create a simple Dynamic Web Project and copy the Jersey JARs to `WebContent/WEB-INF/lib`.

Also, as Qwerky suggested, `web.xml` has to be in `WebContent/WEB-INF/` and `.jar` files should be copied to `WebContent/WEB-INF/lib`.

Other than that, the described procedure looks fine!

Problem

I am following this tutorial to create a REst Service using Jersey. Sometimes i fail to understand fully what the author of the tutorial means but these are the steps that i have followed so far : 1) Created a dynamic web project and named it : `de.vogella.jersey.first` 2) Installed Maven dependencies on eclipse 3) Converted my project to a Maven project (that means created a pom.xml file) 4) Added the necessary dependencies in `pom.xml` so that i can use jersey without having to manually add the jar files. I added the following xml : ``` <dependencies> <dependency> <groupId>com.sun.jersey</groupId> <artifactId>jersey-server</artifactId> <version>1.17.1</version> </dependency> </dependencies> ``` 5) The author suggests to create a java class and gives some code. I can only assume that he wants us to create a new package in the src folder , name it `de.vogella.jersey.first` and then create a java class and name it `Hello` and place the code there. Thats what i did. 6) Then he suggests to open the `web.xml` file. Theres not such a file in the project though. So i go ahead and create such a file in the `WebContent/WEB-INF/lib` path. I place the code that he suggest. 7) Next is the step that i fail to understand most. He talks about the `web.xml` that we just added and more specifically he states: "The parameter "com.sun.jersey.config.property.package" defines in which package jersey will look for the web service classes. This property must point to your resources classes. " 8) Last step is open the URL `http://localhost:8080/de.vogella.jersey.first/rest/hello` in my browser. However i get `HTTP Status 404 - /de.vogella.jersey.first/rest/hello` With what shall i replace exactly the `com.sun.jersey.config.property.package` ? Are the steps that i have followed till now correct , or i misinterpreted something?

Original source