C++11 std::begin doesn't work with int[] passed into template function
c++, c++11, templates
Solution
void heapSort(T array[]);
is just alternative syntax for
void heapSort(T* array);
You can't pass an array by value, so you need to take it by reference (and possibly let the compiler deduce its size):
template<typename T, size_t N>
void heapSort(T (&array)[N]);
Note that this way you'll get a different instantiation for each array of distinct size. It might lead to some code bloat if you've got a large number of arrays. I'd consider using a `std::vector` instead.
Problem
I've got an issue: no matching function for call to ‘begin(int*&)’ The only hint I've found on it is that compiler might not know the size of array at compile time, but I believe that's not my case. Here is what I've got: ``` template <typename T> void heapSort(T array[]) { size_t length = std::end(array) - std::begin(array); if (length == 0) { return; } Heap<T> heap(array); for (size_t i = length - 1; i >= 0; --i) { array[i] = heap.pop(); } } int main() { int array[] = {9, 8, 10, 99, 100, 0}; for (auto i = 0; i < 6; ++i) { std::cout << array[i] << " "; } std::cout << std::endl; heapSort(array); for (auto i = 0; i < 6; ++i) { std::cout << array[i] << " "; } std::cout << std::endl; } ``` What's the problem? How can I solve it?