Django Replace with space from underscore in templates

django, django-templates, python

Solution

If this should be the default output when using `{{ object }}`, then you should override the `__unicode__` method of your model like this:

class MyModel(models.Model):
  title = models.CharField(...)  # this field may hold our string "New_Mexico"
  ...
  def __unicode__(self):
    return self.title.replace('_', ' ')

A different approach might be using `{{ object.human_readable_title }}`, where you define a method in your model:

  def human_readable_title(self):
    return self.title.replace('_', ' ')

I see no reason to build your own template tag for this use case, except you want to use it for many fields of different models.

EDIT: It seems you have a field called "state" in your "jobs" class. So in your case, a solution might be: in your model class create a method

def human_readable_state(self):
  return self.state.replace('_', ' ')

and in the template use:

<label>{{ d.human_readable_state }}</label>

That should do the trick.

Problem

In my database jobs table, state field having values "New_Mexico". But I need to display in html page like "New Mexico". Give some ideas for find and replace. views.py ``` def result(request,user_id): userid=user_id query = Q(emp__companyname=userid) | Q(state=userid ) details=jobs.objects.filter(query).select_related() return render_to_response('result.html', {'details': details}) ``` result.html ``` {% for d in details %} <label>{{ d.state }}</label> {% endfor %} ```

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