Scanf unsigned char in hex

c, hex, scanf, unsigned-char

Solution

Your code is correct for C99 and later. Presumably you are using a C standard library that does not support the `hh` length modifier, which was introduced in C99; probably the Microsoft C standard library.

If you need to support this old C standard library, you will have to rewrite your code to be C89-compatible, for example:

unsigned p[6];

if (scanf("%x.%x.%x.%x.%x.%x", &p[0], &p[1], &p[2], &p[3], &p[4], &p[5]) == 6)
{
    int i;
    for (i = 0; i < 6; i++)
        paket[i] = p[i];
}

Problem

I am trying to change data in array, this is part of my code: ``` u_char paket[100]; //here i put some data into array and then trying to change it by user scanf("%hhx.%hhx.%hhx.%hhx.%hhx.%hhx", &paket[0], &paket[1], &paket[2], &paket[3], &paket[4], &paket[5]); ``` When my input is for example `88.88.88.88.88.88` it sets `paket[0] - paket[5]` to 88, but it also changes `paket[6],` `paket[7]` and `paket[8]` to 0. How is it possible and how to fix it please? I need to change only `[0] - [5]`

Original source