Python regular expression match with file extension

python, regex

Solution

You need to use `.search()` instead; `.match()` anchors to the start of the string. Your pattern is otherwise fine:

>>> re.search('_(\d+)\.txt$', '000014_L_20111026T194928_12.txt')
<_sre.SRE_Match object at 0x10e8b40a8>
>>> re.search('_(\d+)\.txt$', '000014_L_20111026T194928_12.txt').group(1)
'12'

Problem

I want to use Python regular expression utility to find the files which has this pattern: ``` 000014_L_20111026T194932_1.txt 000014_L_20111026T194937_2.txt ... 000014_L_20111026T194928_12.txt ``` So the files I want have an underscore '_' followed by a number (1 or more digits) and then followed by '.txt' as the extension. I used the following regular expression but it didn't match the above names: ``` match = re.match('_(\d+)\.txt$', file) ``` What should be the correct regex to match the file names?

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