How to construct and display the info in simple_list_item_2?

I get the list of customer info from my (testing) database, and I want to display it. The customer is represented by the `Customer` class with `name`, `info`, and `note` members. Its `toString` method returns only the `name`. I have created the `DemoDatabaseMainActivity` that uses the `simple_list_item_1` layout only, thus displaying only the `name` of a customer -- like this: ``` public class DemoDatabaseMainActivity extends ListActivity { private CustomerDataSource datasource; @Override protected void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.main); datasource = new CustomerDataSource(this); datasource.open(); List<Customer> values = datasource.getAllCustomers(); ArrayAdapter<Customer> adapter = new ArrayAdapter<Customer>(this, android.R.layout.simple_list_item_1, values); setListAdapter(adapter); } ... } ``` It works just fine; however, I'd like to learn the next step... I would like to modify the code so that I could use the `android.R.layout.simple_list_item_2` where `name` would be at the first line, and the `info` + `note` at the second line? What should be implemented instead of the `Customer.toString()`, and what adapter or whatever should I use? Update based on Patric's comment https://stackoverflow.com/a/16062742/1346705 -- with respect to that, I have hoped for the modified solution like that: ``` public class DemoDatabaseMainActivity extends ListActivity { private CustomerDataSource datasource; @Override protected void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.main); datasource = new CustomerDataSource(this); datasource.open(); List<Customer> values = datasource.getAllCustomers(); TwolineAdapter adapter = new TwolineAdapter(this, values); // here the difference setListAdapter(adapter); } ... } ``` So, I have added my `TwolineAdapter` class this way: ``` public class TwolineAdapter extends ArrayAdapter<Customer> { private List<Customer> objects; public TwolineAdapter(Context context, List<Customer> objects) { super(context, android.R.layout.simple_list_item_2, objects); this.objects = objects; } @Override public View getView(int position, View convertView, ViewGroup parent) { View view = super.getView(position, convertView, parent); TextView text1 = (TextView) view.findViewById(android.R.id.text1); TextView text2 = (TextView) view.findViewById(android.R.id.text2); text1.setText(objects.get(position).getName()); text2.setText(objects.get(position).getInfo() + " (" + objects.get(position).getNote() + ")"); return view; } } ``` But it did not work (apparently because of some of my errors). Notice the `simple_list_item_2` in the `super` constructor code call. When running, the code shows the error log message like: ``` E/ArrayAdapter(27961): You must supply a resource ID for a TextView ``` I would like to ask you where the problem is. Trying to find the reason, I have modified the `TwolineAdapter` to work the same way as the original with the `simple_list_item_1` ``` public class TwolineAdapter extends ArrayAdapter<Customer> { private List<Customer> objects; public TwolineAdapter(Context context, List<Customer> objects) { super(context, android.R.layout.simple_list_item_1, objects); this.objects = objects; } @Override public View getView(int position, View convertView, ViewGroup parent) { TextView view = (TextView)super.getView(position, convertView, parent); view.setText(objects.get(position).getInfo()); // displaying a different info return view; } } ``` To be sure the overriden `getView` works, I have displayed a different part of the customer info. And it worked fine. In other words, instead of the general `toString` method, the result of my specific `getInfo` was displayed. Anyway, I need to use the `simple_list_item_2`. What next should I do? (My conclusion is I am doing something wrong in the constructor. Am I right? Where is the problem?)