How to get the cwd (current working directory) from a nodejs child process (in both windows and linuxish)

node.js, process

Solution

to start child with parent dir as cwd:

var exec = require('child_process').exec;
var path = require('path')

var parentDir = path.resolve(process.cwd(), '..');
exec('doSomethingThere', {cwd: parentDir}, function (error, stdout, stderr) {
  // if you also want to change current process working directory:
  process.chdir(parentDir);
});

Update: if you want to retrieve child's cwd:

var fs = require('fs');
var os = require('os');
var exec = require('child_process').exec;

function getCWD(pid, callback) {
  switch (os.type()) {
  case 'Linux':
    fs.readlink('/proc/' + pid + '/cwd', callback); break;
  case 'Darwin':
    exec('lsof -a -d cwd -p ' + pid + ' | tail -1 | awk \'{print $9}\'', callback);
    break;
  default:
    callback('unsupported OS');
  }
}

// start your child process
//    note that you can't do like this, as you launch shell process 
//    and shell's child don't change it's cwd:
// var child1 = exec('cd .. & sleep 1 && cd .. sleep 1');
var child1 = exec('some process that changes cwd using chdir syscall');

// watch it changing cwd:
var i = setInterval(getCWD.bind(null, child1.pid, console.log), 100);
child1.on('exit', clearInterval.bind(null, i));

Problem

I'm trying to run a script via nodejs that does: ``` cd .. doSomethingThere[] ``` However, to do this, I need to executed multiple child processes and carry over the environment state between those processes. What i'd like to do is: ``` var exec = require('child_process').exec; var child1 = exec('cd ..', function (error, stdout, stderr) { var child2 = exec('cd ..', child1.environment, function (error, stdout, stderr) { }); }); ``` or at very least: ``` var exec = require('child_process').exec; var child1 = exec('cd ..', function (error, stdout, stderr) { var child2 = exec('cd ..', {cwd: child1.process.cwd()}, function (error, stdout, stderr) { }); }); ``` How can I do this?

Original source