Mixed increment operators with logical operators
c, increment, logical-operators, pre-increment
Solution
This is what you get from short circuiting. `++i` is -2, and the rest doesn't have to be evaluated (and isn't according to the standard). The left side of `||` is true because -2 is not 0, so the whole expression is true.
Problem
I have a question concerning pre and post increments with logical operators if I have this code ``` void main() {int i = - 3 , j = 2 , k = 0 , m ; m=++i||++j&&++k; printf("%d %d %d %d",i,j,k,m);} ``` knowing that the increment and the decrement operators have higher precedence than && and || So they'll be executed first Then the && is higher than means -2||3&&1 which gives the values -2 3 1 1 for the printf but the output I get when trying on VS2010 is -2 2 0 1 Does anyone have any explanation for that ? Regards,,