Printing a column in an matrix without numpy
arrays, matrix, python
Solution
What you have is a list of lists - so there is no concept of a column there. There are two ways to do this, one is (as Pavel Anossov's answer shows) is to use a list comprehension.
One is to use `zip()` which can be used to transpose an iterable:
>>> list(zip(*matrix))
[(0, 3, 9, 10), (1, 7, 4, 3)]
I've made it a list here to make it easier to show the output. Note in 2.x, `zip()` gives a list rather than an iterator (although a lazy version is available as `itertools.izip()`).
Generally, I would use `zip()` if you plan on working with more than one column, and the list comprehension if you only need one.
Problem
I'm really new to programming, so I apologize if this is a really simple question, but i've been trying to print the first column in a matrix without the use of numpy, however it prints like so: ``` matrix = \ [[0, 1], [3, 7], [9, 4], [10, 3]] print matrix[0:3][0] [0, 1] ``` I've also tried: ``` print matrix[:][0] [0, 1] print matrix[:3] [[0, 1], [3, 7], [9, 4]] print matrix[:3][0] [[0, 1], [3, 7], [9, 4]] ``` The answer I'm trying to achieve is: ``` print matrix[code] 0, 3, 9, 10 ``` or similar.