Python , Printing Hex removes first 0?
hex, python
Solution
This is happening because `hex()` will not include any leading zeros, for example:
>>> hex(15)[2:]
'f'
To make sure you always get two characters, you can use `str.zfill()` to add a leading zero when necessary:
>>> hex(15)[2:].zfill(2)
'0f'
Here is what it would look like in your code:
fc = '0x'
for i in b[0x15c:0x15f]:
fc += hex(ord(i))[2:].zfill(2)
Problem
take a look at this: ``` fc = '0x' for i in b[0x15c:0x15f]: fc += hex(ord(i))[2:] ``` Lets say this code found the hex 00 04 0f , instead of writing it that way , it removes the first 0 , and writes : 04f any help?