How to set a default value for a splat argument in Ruby
ruby, splat
Solution
Your attempted usage is counter the conventions around splat usage. Splats are supposed (at least in Ruby) to take up all extra (0, 1 or more) values.
If you know that you want the second value in your method arguments list to have a default value, you could take it out of the splat and list it just before the splat with a default value like this:
def a b, c=nil, *d
# rest of code omitted
end
EDIT: To make the answer to your question of why it doesn't work perfectly clear. It's a design decision by the language designer. Matz never intended the splat operator to work with defaults. This seems pretty sensible to me since it is intended to be used for catching an indeterminate number of variables and because the method I described reads more clearly than the possibilities you described and because all of the problems your examples solve are solvable in other ways.
Problem
Setting a default value for a splat argument gives an error: ``` 1.9.3-p374 :001 > def a b, *c = nil 1.9.3-p374 :002?> end SyntaxError: (irb):1: syntax error, unexpected '=', expecting ';' or '\n' def a b, *c = nil ^ from /Users/me/.rvm/rubies/ruby-1.9.3-p374/bin/irb:16:in `<main>' ``` Some variations I tried that don't work either: ``` 1.9.3-p374 :003 > def a b, *c = [] 1.9.3-p374 :005 > def a b, (*c) = nil 1.9.3-p374 :007 > def a b, (*c = []) 1.9.3-p374 :009 > def a b, (*c = [1,2,3]) 1.9.3-p374 :011 > def a b, *c = [1,2,3] ``` I don't see an indeterminacy issue here, so it seems like it should be possible. Related: Why non-explicit splat param plus default param is wrong syntax for method definition in Ruby 1.9?