Exception Handling in C++ by throwing a string

c++

Solution

String literals have type `char const[]`, decaying to `char const*`. You should adjust your `catch` handler accordingly:

catch (char const* msg)
//          ^^^^^
{
    cout << msg;
}

Here is a live example.

Finally, here is a better way to rewrite your program, using exception classes from the C++ Standard Library:

#include <iostream>
#include <stdexcept>
//       ^^^^^^^^^^^ For std::logic_error

int divn(int n, int d)
{
    if(d == 0)
    {
        throw std::logic_error("Division by ZERO not possible ");
        //    ^^^^^^^^^^^^^^^^
        //    Throw by value
    }

    return n/d;
}

int main() // <== You should specify the return type of main()!
{
    // Rather use these than "using namespace std;"
    using std::cout;
    using std::cin;
    using std::endl;

    int numer, denom;
    cout << "Enter the numerator and denominator : ";
    cin >> numer >> denom;

    try
    {
        cout << numer << " / " << denom << " = " << divn(numer,denom) << endl;
    }
    catch(std::logic_error const& err)
    //    ^^^^^^^^^^^^^^^^^^^^^^^
    //    Catch by reference
    {
        cout << err.what();
        //      ^^^^^^^^^^
    }

    cout << "\nEnd of main() \n ";
}

And the corresponding live example of course.

Problem

Original source