wstring::find() doesn't work with non-latin symbols?
c++, setlocale, stl, wstring
Solution
The encoding of your source file and the execution environment's encoding may be wildly different. C++ makes no guarantees about any of this. You can check this by outputting the hexadecimal value of your string literal:
std::wcout << std::hex << L"ф";
Before C++11, you could use non-ASCII characters in source code by using their hex values:
"\x05" "five"
C++11 adds the ability to specify their Unicode value, which in your case would be
L"\u03A6"
If you're going full C++11 (and your environment ensures these are encoded in UTF-*), you can use any of `char`, `char16_t`, or `char32_t`, and do:
const char* phi_utf8 = "\u03A6";
const char16_t* phi_utf16 = u"\u03A6";
const char32_t* phi_utf16 = U"\u03A6";
Problem
I have an wide-character string (std::wstring) in my code, and I need to search wide character in it. I use find() function for it: ``` wcin >> str; wcout << ((str.find(L'ф') != wstring::npos)? L"EXIST":L"NONE"); ``` `L'ф'` is a Cyrillic letter. But find() in same call always returns `npos`. In a case with Latin letters find() works correctly. It is a problem of this function? Or I incorrectly do something? UPD I use MinGW and save source in UTF-8. I also set locale with `setlocale(LC_ALL, "");`. Code same `wcout << L'ф';` works coorectly. But same ``` wchar_t w; wcin >> w; wcout << w; ``` works incorrectly. It is strange. Earlier I had no problems with the encoding, using setlocale ().