Why can't I pass a directory as an argument to a for loop in bash?
bash, directory
Solution
If you take "$1", it is the first file/directory, which is possible! You should do it in this way:
for i in "$@"
do
echo The current file is ${i}
done
If you execute it with:
./simple.sh *
They list you all files of the actual dictionary
"$1" is alphabetical the first file/directory of your current directory, and in the for loop, the value of "i" would be e.g. a1.sh and then they would go out of the for loop! If you do:
DIR=/home/<s.th.>/*
you save the value of all files/directories in DIR!
Problem
I have a simple bash script, simple.sh, as follows: ``` #/usr/local/bin/bash for i in $1 do echo The current file is $i done ``` When I run it with the following argument: ``` ./simple.sh /home/test/* ``` it would only print and list out the first file located in the directory. However, if I change my simple.sh to: ``` #/usr/local/bin/bash DIR=/home/test/* for i in $DIR do echo The current file is $i done ``` it would correctly print out the files within the directory. Can someone help explain why the argument being passed is not showing the same result?