Why is Ruby's Float#round behavior different than Python's?
floating-accuracy, python, rounding, ruby
Solution
Summary
Both implementations are confront the same issues surrounding binary floating point numbers.
Ruby operates directly on the floating point number with simple operations (multiply by a power of ten, adjust, and truncate).
Python converts the binary floating point number to a string using David Gay's sophisticated algorithm that yields the shortest decimal representation that is exactly equal to the binary floating point number. This does not do any additional rounding, it is an exact conversion to a string.
With the shortest string representation in-hand, Python rounds to the appropriate number of decimal places using exact string operations. The goal of the float-to-string conversion is to attempt to "undo" some of the binary floating point representation error (i.e. if you enter 6.6, Python rounds on the 6.6 rather that 6.5999999999999996.
In addition, Ruby differs from some versions of Python in rounding modes: round-away-from-zero versus round-half-even.
Detail
Ruby doesn't cheat. It starts with plain old binary float point numbers the same a Python does. Accordingly, it is subject to some of the same challenges (such 3.35 being represented at slightly more than 3.35 and 4.35 being represented as slightly less than 4.35):
>>> Decimal.from_float(3.35)
Decimal('3.350000000000000088817841970012523233890533447265625')
>>> Decimal.from_float(4.35)
Decimal('4.3499999999999996447286321199499070644378662109375')
The best way to see the implementation differences is to look at the underlying source code:
Here's a link to the Ruby source code: https://github.com/ruby/ruby/blob/trunk/numeric.c#L1587
The Python source is starts here: http://hg.python.org/cpython/file/37352a3ccd54/Python/bltinmodule.c and finishes here: http://hg.python.org/cpython/file/37352a3ccd54/Objects/floatobject.c#l1080
The latter has an extensive comment that reveals the differences between the two implementations:
The basic idea is very simple: convert and round the double to a decimal string using _Py_dg_dtoa, then convert that decimal string back to a double with _Py_dg_strtod. There's one minor difficulty: Python 2.x expects round to do round-half-away-from-zero, while _Py_dg_dtoa does round-half-to-even. So we need some way to detect and correct the halfway cases.
Detection: a halfway value has the form k * 0.5 * 10**-ndigits for some odd integer k. Or in other words, a rational number x is exactly halfway between two multiples of 10**-ndigits if its 2-valuation is exactly -ndigits-1 and its 5-valuation is at least -ndigits. For ndigits >= 0 the latter condition is automatically satisfied for a binary float x, since any such float has nonnegative 5-valuation. For 0 > ndigits >= -22, x needs to be an integral multiple of 5**-ndigits; we can check this using fmod. For -22 > ndigits, there are no halfway cases: 5**23 takes 54 bits to represent exactly, so any odd multiple of 0.5 * 10**n for n >= 23 takes at least 54 bits of precision to represent exactly.
Correction: a simple strategy for dealing with halfway cases is to (for the halfway cases only) call _Py_dg_dtoa with an argument of ndigits+1 instead of ndigits (thus doing an exact conversion to decimal), round the resulting string manually, and then convert back using _Py_dg_strtod.
In short, Python 2.7 goes to great lengths to accurately follow a round-away-from-zero rule.
In Python 3.3, it goes to equally great length to accurately follow a round-to-even rule.
Here's a little additional detail on the _Py_dg_dtoa function. Python calls the float to string function because it implements an algorithm that gives the shortest possible string representation among equal alternatives. In Python 2.6, for example, the number 1.1 shows up as 1.1000000000000001, but in Python 2.7 and later, it is simply 1.1. David Gay's sophisticated dtoa.c algorithm gives "the-result-that-people-expect" without forgoing accuracy.
That string conversion algorithm tends to make-up for some of the issues that plague any implementation of round() on binary floating point numbers (i.e. it less rounding of 4.35 start with 4.35 instead of 4.3499999999999996447286321199499070644378662109375).
That and the rounding mode (round-half-even vs round-away-from-zero) are the essential differences between the Python and Ruby round() functions.
Problem
"Behavior of “round” function in Python" observes that Python rounds floats like this: ``` >>> round(0.45, 1) 0.5 >>> round(1.45, 1) 1.4 >>> round(2.45, 1) 2.5 >>> round(3.45, 1) 3.5 >>> round(4.45, 1) 4.5 >>> round(5.45, 1) 5.5 >>> round(6.45, 1) 6.5 >>> round(7.45, 1) 7.5 >>> round(8.45, 1) 8.4 >>> round(9.45, 1) 9.4 ``` The accepted answer confirms this is caused by the binary representation of floats being inaccurate, which is all logical. Assuming that Ruby floats are just as inaccurate as Python's, how come Ruby floats round like a human would? Does Ruby cheat? ``` 1.9.3p194 :009 > 0.upto(9) do |n| 1.9.3p194 :010 > puts (n+0.45).round(1) 1.9.3p194 :011?> end 0.5 1.5 2.5 3.5 4.5 5.5 6.5 7.5 8.5 9.5 ```