Efficient way to create list of same numbers?

Question

What is the most efficient way to create list of the same number with n elements?

Accepted Answer

```
number = 1
elements = 1000

thelist = [number] * elements
```

```
>>> [1] * 10
[1, 1, 1, 1, 1, 1, 1, 1, 1, 1]
```

NB: Don't try to duplicate mutable objects (notably lists of lists) like that, or this will happen:

```
In [23]: a = [[0]] * 10

In [24]: a
Out[24]: [[0], [0], [0], [0], [0], [0], [0], [0], [0], [0]]

In [25]: a[0][0] = 1

In [26]: a
Out[26]: [[1], [1], [1], [1], [1], [1], [1], [1], [1], [1]]
```

If you are using numpy, for multidimensional lists `numpy.repeat` is your best bet. It can repeat arrays of all shapes over separate axes.

Solution