How do I return a hash with a case statement?

hashmap, ruby

Solution

You need to use a bare `case` statement if you want to use an expression inside each `when` clause. Otherwise, Ruby will call `(days <= 31) === days`, which will never be true.

def number_to_date(days)
  date = case
    when days <= 31  then {"month" => "January",   "day" => days}
    when days <= 59  then {"month" => "February",  "day" => (days - 31)}
    # ...
  end
  return date
end

This implementation however ignores leap days and it seems simpler and more correct to just do this:

def number_to_date(days)
  date = Date.ordinal(Date.today.year, days)
  {"month" => Date::MONTHNAMES[date.month], "day" => date.day}
end

Problem

I am trying to write a function that takes the day number of the date, for example, today (March 29) is the 88th day of the year. It then returns a hash containing the month, and the day in the month: ``` {"month" => "March, "day" => 29} ``` I can't quite figure out what is wrong with this code, but it always returns `nil`. Any thoughts? I am using Ruby 1.8.7 p358. ``` def number_to_date(days) date = case days when days <= 31 then {"month" => "January", "day" => days} when days <= 59 then {"month" => "February", "day" => (days - 31)} when days <= 90 then {"month" => "March", "day" => (days - 59)} when days <= 120 then {"month" => "April", "day" => (days - 90)} when days <= 151 then {"month" => "May", "day" => (days - 120)} when days <= 181 then {"month" => "June", "day" => (days - 151)} when days <= 212 then {"month" => "July", "day" => (days - 181)} when days <= 243 then {"month" => "August", "day" => (days - 212)} when days <= 273 then {"month" => "September", "day" => (days - 243)} when days <= 304 then {"month" => "October", "day" => (days - 273)} when days <= 334 then {"month" => "November", "day" => (days - 304)} when days <= 365 then {"month" => "December", "day" => (days - 334)} end return date end ```

Original source